Integrand size = 15, antiderivative size = 152 \[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=\frac {7 b^3 x^2}{40 a^3 \sqrt [4]{a+b x^4}}-\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}-\frac {7 b^2 \left (a+b x^4\right )^{3/4}}{40 a^3 x^2}-\frac {7 b^{5/2} \sqrt [4]{1+\frac {b x^4}{a}} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{40 a^{5/2} \sqrt [4]{a+b x^4}} \]
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Time = 0.07 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {281, 331, 235, 233, 202} \[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=-\frac {7 b^{5/2} \sqrt [4]{\frac {b x^4}{a}+1} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{40 a^{5/2} \sqrt [4]{a+b x^4}}+\frac {7 b^3 x^2}{40 a^3 \sqrt [4]{a+b x^4}}-\frac {7 b^2 \left (a+b x^4\right )^{3/4}}{40 a^3 x^2}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}-\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}} \]
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Rule 202
Rule 233
Rule 235
Rule 281
Rule 331
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {1}{x^6 \sqrt [4]{a+b x^2}} \, dx,x,x^2\right ) \\ & = -\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}-\frac {(7 b) \text {Subst}\left (\int \frac {1}{x^4 \sqrt [4]{a+b x^2}} \, dx,x,x^2\right )}{20 a} \\ & = -\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}+\frac {\left (7 b^2\right ) \text {Subst}\left (\int \frac {1}{x^2 \sqrt [4]{a+b x^2}} \, dx,x,x^2\right )}{40 a^2} \\ & = -\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}-\frac {7 b^2 \left (a+b x^4\right )^{3/4}}{40 a^3 x^2}+\frac {\left (7 b^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{a+b x^2}} \, dx,x,x^2\right )}{80 a^3} \\ & = -\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}-\frac {7 b^2 \left (a+b x^4\right )^{3/4}}{40 a^3 x^2}+\frac {\left (7 b^3 \sqrt [4]{1+\frac {b x^4}{a}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{1+\frac {b x^2}{a}}} \, dx,x,x^2\right )}{80 a^3 \sqrt [4]{a+b x^4}} \\ & = \frac {7 b^3 x^2}{40 a^3 \sqrt [4]{a+b x^4}}-\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}-\frac {7 b^2 \left (a+b x^4\right )^{3/4}}{40 a^3 x^2}-\frac {\left (7 b^3 \sqrt [4]{1+\frac {b x^4}{a}}\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {b x^2}{a}\right )^{5/4}} \, dx,x,x^2\right )}{80 a^3 \sqrt [4]{a+b x^4}} \\ & = \frac {7 b^3 x^2}{40 a^3 \sqrt [4]{a+b x^4}}-\frac {\left (a+b x^4\right )^{3/4}}{10 a x^{10}}+\frac {7 b \left (a+b x^4\right )^{3/4}}{60 a^2 x^6}-\frac {7 b^2 \left (a+b x^4\right )^{3/4}}{40 a^3 x^2}-\frac {7 b^{5/2} \sqrt [4]{1+\frac {b x^4}{a}} E\left (\left .\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{40 a^{5/2} \sqrt [4]{a+b x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.01 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.34 \[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=-\frac {\sqrt [4]{1+\frac {b x^4}{a}} \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {1}{4},-\frac {3}{2},-\frac {b x^4}{a}\right )}{10 x^{10} \sqrt [4]{a+b x^4}} \]
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\[\int \frac {1}{x^{11} \left (b \,x^{4}+a \right )^{\frac {1}{4}}}d x\]
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\[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=\int { \frac {1}{{\left (b x^{4} + a\right )}^{\frac {1}{4}} x^{11}} \,d x } \]
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Result contains complex when optimal does not.
Time = 0.76 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.21 \[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=- \frac {{{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{2}, \frac {1}{4} \\ - \frac {3}{2} \end {matrix}\middle | {\frac {b x^{4} e^{i \pi }}{a}} \right )}}{10 \sqrt [4]{a} x^{10}} \]
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\[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=\int { \frac {1}{{\left (b x^{4} + a\right )}^{\frac {1}{4}} x^{11}} \,d x } \]
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\[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=\int { \frac {1}{{\left (b x^{4} + a\right )}^{\frac {1}{4}} x^{11}} \,d x } \]
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Timed out. \[ \int \frac {1}{x^{11} \sqrt [4]{a+b x^4}} \, dx=\int \frac {1}{x^{11}\,{\left (b\,x^4+a\right )}^{1/4}} \,d x \]
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